Recent Questions
Q: The popup menu gives the (first) menu of the top menu. I need of course for this to be the menu of the popup.
A: Installation of your menu is not correct.
Now you have:
1) There is no need to call dmenu_popup.js file. You should delete thefollowing line:
<script type="text/javascript" language="JavaScript1.2" src="dmenu_popup.js"></script>
2) Where you call source_pop.js file for Popup menu?
You should add:
<SCRIPT language=JavaScript1.2 src="menu_files/source_pop.js"type=text/javascript></SCRIPT>
3) The ID of your Popup menu is 1. Now you have ID - 0.
<img src="testimage.gif" width="200" height="200" onClick="return dm_popup(0, 9000, event);" style="cursor:hand;">
you should write:
<img src="testimage.gif" width="200" height="200" onClick="returndm_popup(1, 9000, event);" style="cursor:hand;">
Q: I need to work it with PHP/MySQL. I have found some information on it in your Support section, but have problems to understand and wonder if you have more information or a working sample of the loading bar with PHP/ MySQL.
A: Info about generating menu (menu items )from a database, please, see:
http://deluxe-menu.com/generate-menu-from-database-xml-php-asp-vb-support.html
Please, see the example of .php file.
The content of .php file depends on your database structure.
<?php
// The example for PHP/MySQL.
// MySQL database has the table "menuTable" that contains data for menu items.
// The table has the following fields:
// 1. "text" - item text
// 2. "link" - item link
// 3. "icon1" - item icon (normal state)
// 4. "icon2" - item icon (mouseover state)
function getMenuItems()
{
$jsItems = '';
// Select all records from table "menuTable"
$allItems = mysql_query('SELECT * FROM menuTable;');
// Extract items data from database and build Javascript code for menuItems
while ($itemData=mysql_fetch_array($allItems))
{
$jsItems .= '["'.$itemData['text'].'", "'.$itemData['link'].'", "'.$itemData['icon1'].'", "'.$itemData['icon2'].'"],';
}
// Return Javascript code
return $jsItems;
}
?>
<script>
var menuParam1 = value1;
var menuParam2 = value2;
var menuParam2 = value2;
...
var menuItems = [
<?php
// Write Javascript code for menu items
echo getMenuItems();
?>
];
</script>
Q: I would like all my submenus of the html menu to appear in the same location on the page and not relative to the parent menu item.
A: You can do it using the following parameters:
var subMenuAlign = "left"; - Horizontal alignment for submenus.
"pleft", "pcenter", "pright" - alignment relative to the parent submenu.
var subMenuVAlign = "top"; - Submenus vertical alignment.
"ptop", "pcenter", "pbottom" - alignment relative to the parent submenu.
Q: The menu has a problem with newlines. The menu builds correctly (layout ok) but when pressed on the button nothing happens
At some point, in the DHTML menu, we have the following in the javascript:
var menuitems = [
["|Print HTML","javascript:alert('HTML print: Only the 7 most recent orders on the screen \n will be printed because of space limitations on paper.');printResult('4'); ","","", ,"_parent",,] ]
As you can see we have a newline (\n) between the words "screen" and "will". But when we click on the button nothing happens. If we remove the newline and we click on the button then we first get the alert box. After pressing the OK button the function printResult is called.
Is there any way for us to still use the newline character in the menuItems variable?
This can be easily reproducible. That's why I haven't made an example.
A: Try to write in the following way \\n:
["|Print HTML","javascript:alert('HTML print: Only the 7 most recent orders on the screen \\n will be printed because of space limitations on paper.');printResult('4'); ","","", ,"_parent",,]