Recent Questions
Q: I recently received a non-profit license for your product, and after I installed it and the 'trial version' label disappeared, two of my javascript menu frames started appearing "up", instead of "down" which is preferred.
The 'enrollment center' and the 'physician center' work fine. The 'volunteer center' and 'donor center' used to work correctly (down) before I updated to the non-profit license, but now they appear "up".
If you could please help me that would be great.
A: You should set the following parameter:
var subMenuVAlign="top";
Q: Whenver I choose the enable Ajax feature and set the AjaxCount to 0, my menus don't pop out anymore. How do I get it to pop out?
A: That variable set the maximal number of submenus that will be loadedfrom server on your page.
If you don't know exact number of submenus you can set a big value forthis parameter.
If you set var dmAJAXCount=0; you cannot see you submenus.
To enable Ajax feature you should set, for example:
var dmAJAX=1;
var dmAJAXCount=100;
Q: Hello. I am trying to test out your mouse over drop down menu and I am having trouble using the separators. Are there certain things that need to be in placed for the separators to work?
Nothing in the js code is showing me that they even exist.
A: You should set a separator in the menuItems, for example:
var menuItems = [
["Home","index.cfm", , , , , , , , ],
["-"],
["About Us","about.cfm", , , , , , , , ],
];
Please, see the following parameters:
//--- Separators
var separatorImage=""; //for subitems
var separatorWidth="100%";
var separatorHeight="3px";
var separatorAlignment="right";
var separatorVImage="images/public/separator.gif"; //for the top items
var separatorVWidth="100%";
var separatorVHeight="2px";
var separatorPadding="";
Q: Is it possible to have your menu mouseover call one of my functions?
I need to change some text on the screen based on which menu itemis highlighted.
A: Each menu items can include any html code.
So, you can include your own objects with onmouseover event, forexample:
var menuItems = [
["<div onmouseover='yourFunc()'>item text</div>"]
];
Where yourFunc() is Javascript function.